Thank you in advance for your help and please excuse my lack of knowledge or if my terminology isn’t accurate.
I am hoping someone can help me answer a question or two about running some Quantum boards using Meanwell drivers and I want to make sure I’m not overloading a 15 Amp circuit, as well as see how much wattage or amps I have left for other electrical devices on the same 15A circuit.
I have 2x HLG-320H-48AB and 1x HLG-240H-48AB Drivers- all with dimmers and I am running all three on the same 15amp circuit. I have attached a picture of each of them for review and accuracy.
There’s so much information online but I’m not finding a definitive answer that I understand. I’m quite new to this, clearly.
One explanation said take the total watts of the lights which is around 800-880 watts if running all max brightness (or less when they’re dimmed I assume, but for the sake of this scenario let’s assume the max 880), and then divide by the voltage which I believe is 120. That comes out to 7.33 amps. And if I understand correctly, I should keep it 20% below the max which would be 12 available amps. Therefore that would leave approximately 4.67 amps for other electrical devices - if this way of calculating is even correct...
I would sincerely and greatly appreciate any input and help! Thank you guys!
I am hoping someone can help me answer a question or two about running some Quantum boards using Meanwell drivers and I want to make sure I’m not overloading a 15 Amp circuit, as well as see how much wattage or amps I have left for other electrical devices on the same 15A circuit.
I have 2x HLG-320H-48AB and 1x HLG-240H-48AB Drivers- all with dimmers and I am running all three on the same 15amp circuit. I have attached a picture of each of them for review and accuracy.
There’s so much information online but I’m not finding a definitive answer that I understand. I’m quite new to this, clearly.
One explanation said take the total watts of the lights which is around 800-880 watts if running all max brightness (or less when they’re dimmed I assume, but for the sake of this scenario let’s assume the max 880), and then divide by the voltage which I believe is 120. That comes out to 7.33 amps. And if I understand correctly, I should keep it 20% below the max which would be 12 available amps. Therefore that would leave approximately 4.67 amps for other electrical devices - if this way of calculating is even correct...
I would sincerely and greatly appreciate any input and help! Thank you guys!