linear equations

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silasraven

Well-Known Member
went searching on the net for the way to work this out and couldnt find it. so maybe you could help me.

basically it says graph linear equations on the coordinate plane but you have to solve them to do so.

heres one( schools closed for today because of this holiday) y=x+1 now how do i solve with just one number im trying to get rid of X so i can find Y
 
Tenner

Tenner

Well-Known Member
Thats dead easy!

Good luck solving it though, weren`t you the guy who was supporting the killings in gaza by claiming jewish people were promised land by god... lmao
 
billybob420

billybob420

Well-Known Member
You don't have to solve the equation, there's nothing to solve. y=x+1, that's the answer. You just gotta graph it.
 
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redivider

Well-Known Member
simple stuff right there.

and guy is correct. that formula you have right there is the 'answer' in form y = mx+ b. where M is the slope and B is the Y intercept. in your case the Y intercept is +1, slope is 1.

if you can't figure it out from here then i don't know what to tell you...
 
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silasraven

Well-Known Member
redivider said:
simple stuff right there.

and guy is correct. that formula you have right there is the 'answer' in form y = mx+ b. where M is the slope and B is the Y intercept. in your case the Y intercept is +1, slope is 1.

if you can't figure it out from here then i don't know what to tell you...
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so my next problem is y - x=-4, so if i place my first one it's 1,1 and placing my next one its -4,-4 right? for graphing or do i just plot them directly on the line 1 and then -4?
 
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redivider

Well-Known Member
y - x = -4 is also an answer to a linear equation only in a different form.

i always worked better in the y =mx + b form. slope intercept form i think it's called....

y - x = -4 is the same as y= x - 4. y intercept is -4 slope = 1.

y intercept x= 0 y = -4 the next point in front of it would be x = 1. substitute in the original equation. plot second point.

i hope you understand because I kinda remember that whole zionist trip now and I've decided to not help you anymore... good luck!!
 
bostoner

bostoner

Active Member
I think once you get the simplified versions you can type them into google like "graph <blah=blah+blah>" and it graphs it for you. Kind of funny seeing 6th grade school homework again.
 
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silasraven

Well-Known Member
yeah well not all people understand math. i've always had problems understanding the teacher even when its one on one its still confusing.
 
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silasraven

Well-Known Member
23 so i have a problem understand high school algebra so what? every teacher ive ever had has confused me, sometimes they make sense.
 
curious2garden

curious2garden

Well-Known Mod
Staff member
silasraven, I know you don't want to hear this but math (at this level), is a very linear and EASY subject. Meaning you can not move forward unless you understand what came before. Each bit is dependent upon the previous bit. You have asked for help with two linear equations. This means you do not have the concept of linear equations, arithmetic properties and manipulation of variable equations.

You can not cram for math. PLEASE save yourself the trouble and start at the beginning of a beginning Algebra book and work each chapter before you begin the next. That is the only way. The reason you have trouble with math is because you are trying to move beyond a point you do not understand. So you need to back up and get the basics down. Go back to where Math makes sense. That maybe basic mathematics instead of algebra but where ever that point is you MUST start there and understand each concept before you can move forward.

If you do this you'll find that suddenly math is easy and you will understand it.
 
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silasraven

Well-Known Member
^^^^the problem with that is i cant go back. its in the form of packets and we are out for the holiday. im thinking that X is up to me to put on the graph as i want. i got the previous part.which was a table they give you X which was--2,0,2 and you are asked to find y. with y=3x i understood that and got them mostly right. like i said i think the next part is up to me to choose what X is supposed to be.
 
Carne Seca

Carne Seca

Well-Known Member
curious2garden said:
silasraven, I know you don't want to hear this but math (at this level), is a very linear and EASY subject. Meaning you can not move forward unless you understand what came before. Each bit is dependent upon the previous bit. You have asked for help with two linear equations. This means you do not have the concept of linear equations, arithmetic properties and manipulation of variable equations.

You can not cram for math. PLEASE save yourself the trouble and start at the beginning of a beginning Algebra book and work each chapter before you begin the next. That is the only way. The reason you have trouble with math is because you are trying to move beyond a point you do not understand. So you need to back up and get the basics down. Go back to where Math makes sense. That maybe basic mathematics instead of algebra but where ever that point is you MUST start there and understand each concept before you can move forward.

If you do this you'll find that suddenly math is easy and you will understand it.
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silasraven said:
^^^^the problem with that is i cant go back. its in the form of packets and we are out for the holiday. im thinking that X is up to me to put on the graph as i want. i got the previous part.which was a table they give you X which was--2,0,2 and you are asked to find y. with y=3x i understood that and got them mostly right. like i said i think the next part is up to me to choose what X is supposed to be.
Click to expand...
It's the only way Silas. You have to get the basics down before you can progress. Otherwise, you're going to spend the entire course floundering and most likely end up dropping it due to a failing grade. Get thee to a tutor as soon as possible.
 
UncleBuck

UncleBuck

Well-Known Member
i rated this abortion of a thread one star before i even read it. now that i read it, i am validated in my assumption.
 
RyanTheRhino

RyanTheRhino

Well-Known Member
I came in here expecting linear algebra and you ask arithmetic.

This is linear algebra



jk, good luck into your expedition of the math world.
 
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