Spuzzum
Well-Known Member
This is the way I understand it... in series, all led's in string share same current, but voltage is added for each. In parallel, all led's share same voltage, but current is added for each.Well I'm no electrical engineer but electricity takes the path of least resistance so if you parallel wire an LED and Resistor the current goes through the path of least resistance (LED) unless it's burnt out in which case that circuit is then high resistance so it will go through the resistor which is necessary to stop the current increasing in the remaining LED's and causing cascading failure from running too high a current.
Am I missing something?
If say led's use 2.1v @ 350mA, and you have a 24vdc source @ 5 Amps. You can wire 11 led's in series for 23.1v, or 10 in series for 21v. But you still have 4v to "waste", and get down to 350mA...
8575mW - 7350mW = 1225mW, or 1.225 WattsSolution 0: 10 x 1 array uses 10 LEDs exactly
+----|>|----|>|----|>|----|>|----|>|----|>|----|>|----|>|----|>|----|>|---/\/\/----+ R = 10 ohms
The wizard says: In solution 0:
each 10 ohm resistor dissipates 1225 mW
!! the wizard thinks the power dissipated in your resistors is a concern
together, all resistors dissipate 1225 mW
together, the diodes dissipate 7350 mW
total power dissipated by the array is 8575 mW
the array draws current of 350 mA from the source.
Now, if wiring in parallel, you'd need a power source "exactly" 2.1v.. with a lot more amperage than 5 Amps.. unless you want a lot of drivers.
Say you have a 2.3v source, with 50 Amps..
50A / 350mA = 142.857 led's (142)
But, if using the same 10 led example as the series array....
Yes, they're the same... but that's "if" the source is within 0.2v of the actual draw. Raise the source to 3v.. a more "commonly available" power adapter...Solution 0: 1 x 10 array uses 10 LEDs exactly
+----|>|---/\/\/----+ R = 1 ohms
+----|>|---/\/\/----+ R = 1 ohms
+----|>|---/\/\/----+ R = 1 ohms
+----|>|---/\/\/----+ R = 1 ohms
+----|>|---/\/\/----+ R = 1 ohms
+----|>|---/\/\/----+ R = 1 ohms
+----|>|---/\/\/----+ R = 1 ohms
+----|>|---/\/\/----+ R = 1 ohms
+----|>|---/\/\/----+ R = 1 ohms
+----|>|---/\/\/----+ R = 1 ohms
The wizard says: In solution 0:
each 1 ohm resistor dissipates 122.5 mW
the wizard thinks ¼W resistors are fine for your application
together, all resistors dissipate 1225 mW
together, the diodes dissipate 7350 mW
total power dissipated by the array is 8575 mW
the array draws current of 3500 mA from the source.
10657.5mW - 7350mW = 3307.5mW, or 3.3075 WattsSolution 0: 1 x 10 array uses 10 LEDs exactly
+----|>|---/\/\/----+ R = 2.7 ohms
+----|>|---/\/\/----+ R = 2.7 ohms
+----|>|---/\/\/----+ R = 2.7 ohms
+----|>|---/\/\/----+ R = 2.7 ohms
+----|>|---/\/\/----+ R = 2.7 ohms
+----|>|---/\/\/----+ R = 2.7 ohms
+----|>|---/\/\/----+ R = 2.7 ohms
+----|>|---/\/\/----+ R = 2.7 ohms
+----|>|---/\/\/----+ R = 2.7 ohms
+----|>|---/\/\/----+ R = 2.7 ohms
The wizard says: In solution 0:
each 2.7 ohm resistor dissipates 330.75 mW
the wizard thinks 1W resistors are needed for your application
together, all resistors dissipate 3307.5 mW
together, the diodes dissipate 7350 mW
total power dissipated by the array is 10657.5 mW
the array draws current of 3500 mA from the source
3.3075 Watts - 1.225 Watts = 2.0825 Watts (~2.1w)
And that's at 10 led's.. adds up for an entire panel. And that's "if" the source is only 0.9v more than the draw.
Don't forget to factor in the power adapter's ac/dc loss as well.. smaller the adapter's output, less efficient the conversion. Seems that converting 110ac to 48vdc is MORE efficient than converting to 24vdc. And a supply with only 3vdc is even LESS efficient. .. Go figure, eh? Seems those dimmer switches we all had in our dining room chandeliers.. all they did was resist/waste the energy.. unless they were "switching regulators" that turned on and off as the power is needed. Otherwise, they're just a glorified resistor .
http://led.linear1.org/led.wiz
Cheers bud........