Horticulture Lighting Group HLG 350R how much heat compared to other lights?

ilovetoskiatalta

Well-Known Member
Depends what driver you use. Whatever the efficiency of the driver is the rest of the percentage of the watts to to heat. So a driver that concerts 90% of 600w to dc power there will be 60W heat wasted. Or 60x3.41 btu = 204 btu
So what drivers are better? I run 315cmh with a phantom2 ballast. Which drivers are more efficient and more reliable? The premium paid for this 350r is acceptable. Are you telling me that the driver may not be as reliable as my 315cmh phantoms? What band of drivers for LED are more reliable?
 

Rocket Soul

Well-Known Member
One 350 hlg would be a poor change for 2 x 315 due to spread. You could almost change out a 315 with a 240 fixture though. Remember to up your temps a bit when running leds, they need minimum 81F in high intensity conditions
 

ilovetoskiatalta

Well-Known Member
So that driver is 93.5% efficient. So expect 6.5% of the watts to go to heat or 320x 0.065 = 20.8 heat watts or 71 BTU
@MidnightSun72 do you have to break led lights in? In the past I always started a ballast and new bulb at the beginning of a daily cycle? Do you have to do anything special? Do you have to wait for a cool down after you turn them off to restart? I have heard the intensity is overpowering to plants so I started the light at 30% to see how they react. Is the 93.5% efficient rate really only 87% then? It says it has an efficacy 2.69/2.75. How do I compare that to a 315cmh?
 

PJ Diaz

Well-Known Member
He calculated it, 1 watt = 3.412142 BTU. It makes no difference if it's CMH, LED or a vacuum cleaner.
I'm not completely sure I totally agree with this. I think we also have to consider how those watts have been converted to other forms of energy. I'm fairly certain that a 500w refrigerator with the door left open in a small enclosed room will create an environment cooler than a 500watt heater in the same enclosed room. I believe that the heat from the 1watt to 3.41 btu formula is only additive to the wattage's energy conversion itself.
 

MidnightSun72

Well-Known Member
I'm not completely sure I totally agree with this. I think we also have to consider how those watts have been converted to other forms of energy. I'm fairly certain that a 500w refrigerator with the door left open in a small enclosed room will create an environment cooler than a 500watt heater in the same enclosed room. I believe that the heat from the 1watt to 3.41 btu formula is only additive to the wattage's energy conversion itself.
If you leave a fridge with the door open in a room the room will get hotter. The fridge only gets colder because your fridge is sucking out the heat energy from inside and dumping to outside of the insulated area. But the process has losses as the compressors are not 100% efficient so they will waste some energy as heat. So your net heat your room will go up.

there has to be a conservation of energy so whatever coldness is inside the fridge there has the be equal hotness coming out.

also with the lights you are thinking if an LED is making more photons and thus less heat. Then a 600W LED should leave less heat in the room than a 600w HPS right?

what you might not be considering is that once photons hit objects in the room and change their wavelengths they disperse their energy as heat... so eventually all the watts you spend in your room become heat.
 

PJ Diaz

Well-Known Member
If you leave a fridge with the door open in a room the room will get hotter. The fridge only gets colder because your fridge is sucking out the heat energy from inside and dumping to outside of the insulated area. But the process has losses as the compressors are not 100% efficient so they will waste some energy as heat. So your net heat your room will go up.

there has to be a conservation of energy so whatever coldness is inside the fridge there has the be equal hotness coming out.

also with the lights you are thinking if an LED is making more photons and thus less heat. Then a 600W LED should leave less heat in the room than a 600w HPS right?

what you might not be considering is that once photons hit objects in the room and change their wavelengths they disperse their energy as heat... so eventually all the watts you spend in your room become heat.
Then why are some types of heaters more efficient than others? Asking for a friend.
 

MidnightSun72

Well-Known Member
@MidnightSun72 do you have to break led lights in? In the past I always started a ballast and new bulb at the beginning of a daily cycle? Do you have to do anything special? Do you have to wait for a cool down after you turn them off to restart? I have heard the intensity is overpowering to plants so I started the light at 30% to see how they react. Is the 93.5% efficient rate really only 87% then? It says it has an efficacy 2.69/2.75. How do I compare that to a 315cmh?
No you don't break LEDs in. I don't know of any light that needs broken in. I don't know everything lol. One of the best thing about LEDs is they turn on and off with the power with no problem no cool down period.
I am not sure how you got 87 percent efficiency out of 93.5? Basically if you are running 600W worth of lights then the driver should be drawing 600w/0.935= 641.7W from the wall. CMH lights makes around 1.9-2.0 efficacy so comparing to the LED say 1.95 vs 2.7.
 

PJ Diaz

Well-Known Member
Ok well reference something that shows me differently? I am not married to my ideas. Maybe you understand it better than I do. But you aren't communicating how, you are just referencing your intuition.

When referring to the efficiency of an appliance or energy system, we are actually talking about how much energy that system must use to perform a certain amount of work. The higher its energy consumption per unit of output, the less efficient the system is. For example, an air conditioner that requires 750 watts of electricity to provide 6,000 Btu of cooling will be less efficient than one that can provide the same amount of cooling for only 500 watts.
Surely in the example above, the AC unit which provides 6,000 btu of cooling for 500w of consumption will operate a cooler room than the 750w AC unit which provides the same btu of cooling. In your narrow view of watt to btu conversion, you don't consider how or what those watts are being converted to. It's simply a one dimensional perspective.
 

PJ Diaz

Well-Known Member
An air conditioner is transferring the heat outside the room by compressing and expanding a gas. Taking the heat from in the room to outside the room. That's why the wattage of the AC isn't adding heat to the room.

You sound like you are just trying to troll so feel free to cool your room with a refrigerator and whatever other genius ideas you come up with and let us know how great they work out
So your assertion is that a more efficient AC unit transfers more heat outside, despite being the same wattage as a less efficient unit? That seems to fly in the face of your entire argument.
 

MidnightSun72

Well-Known Member
So your assertion is that a more efficient AC unit transfers more heat outside, despite being the same wattage as a less efficient unit? That seems to fly in the face of your entire argument.
You would be right if the AC was spending all of its wattage in the room. But it's not. The only wattage an AC is putting in the room is the fan to blow the cold air. The condenser unit is always outside. Otherwise like the refrigerator it would heat the room.

believe whatever you want. Best of luck on your grows.
 

PJ Diaz

Well-Known Member
You would be right if the AC was spending all of its wattage in the room. But it's not. The only wattage an AC is putting in the room is the fan to blow the cold air. The condenser unit is always outside. Otherwise like the refrigerator it would heat the room.

believe whatever you want. Best of luck on your grows.
An AC unit does a lot more than simply diverting warm air outside. That's what efficiency is all about. If you want to disregard efficiency for simple wattage burn to btu conversion, you are missing out on half of the story.
 
Top