indoor plants

valhalla88

Active Member
I was wondering if it would be helpfull in the last week to take my girls outside in the natural light...like on my deck...
I am asking because well I don't want to shock them but my brain is itching to find out ...I mean the sun is a great source of light and it's free.
Temps are in the upper 60's mid 70's...
trell me what you know!
Has anyone done this & if so what were the results???
Thanks in advance:weed:
 

SCARHOLE

Well-Known Member
Mellow temps are good time to hardem em outside, I just moved one outside with no hardenig cause its so nice now (days are cool nights arent to cold).
The suns over 10,000 lumens so it would be more light , but you risk them being seen.
On the week ends i move my autos out into the sun for extra fuel, they are easy to hide, but a taller plant i wouldnt even bother unless its realy hot when you decide to move em outdoors perminatly.
.
 

valhalla88

Active Member
Mellow temps are good time to hardem em outside, I just moved one outside with no hardenig cause its so nice now (days are cool nights arent to cold).
The suns over 10,000 lumens so it would be more light , but you risk them being seen.
On the week ends i move my autos out into the sun for extra fuel, they are easy to hide, but a taller plant i wouldnt even bother unless its realy hot when you decide to move em outdoors perminatly.
.
I'm in the sticks not worried about them being seen...but only 10,000 lumens? shit my 400 watt conversion mh sunmater is 36,000...how can that be more light then the sun...and the sun has a complete spectrum.
So I'm just wondering....really no benefit huh?
 

SCARHOLE

Well-Known Member
It wa 10,000 lux on a cloudy day, lol

Digging around, I found....................

that bright sunlight is 50K-100K lux. Let's go halvies on that, and say 75K lux.




Now, lux is defined as lumens per square meter. So, we are measuring 75,000 lumens per square meter at the Earth's surface. All we have to do is find the number of square meters on the surface of a sphere with a radius equal to the Earth's distance from the sun.

The Earth is about 150 million km from the sun (150 billion meters). The formula for the area of a sphere of radius r is 4(pi)r^2.

Thus, the sphere has a surface area of 4(pi)(150x10^9)^2 = 2.83*10^23 square meters.

Multiply that by the lux value from before (75,000 lux = 75,000 lumens/m^2) and we get 2.12x10^28 lumens.
 

valhalla88

Active Member
It wa 10,000 lux on a cloudy day, lol

Digging around, I found....................

that bright sunlight is 50K-100K lux. Let's go halvies on that, and say 75K lux.




Now, lux is defined as lumens per square meter. So, we are measuring 75,000 lumens per square meter at the Earth's surface. All we have to do is find the number of square meters on the surface of a sphere with a radius equal to the Earth's distance from the sun.

The Earth is about 150 million km from the sun (150 billion meters). The formula for the area of a sphere of radius r is 4(pi)r^2.

Thus, the sphere has a surface area of 4(pi)(150x10^9)^2 = 2.83*10^23 square meters.

Multiply that by the lux value from before (75,000 lux = 75,000 lumens/m^2) and we get 2.12x10^28 lumens.
is that all? lmao! thats alot bro and I just
got up! lol I'll have to look at that when my eyes are open thanx! lol
 
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