Here are the specs.
http://www.meanwell.com/mw_search/hlg-240h/HLG-240H-SPEC.PDF
I'm just learning this stuff and If I understand the calculations correctly (please school me if I'm wrong
) the voltage range is 127 ~ 431VDC and figuring the cob dcv is 36v that would mean you can up to 12 cobs (431VDC divided by 36V = 11.97222.
I think this is where the amperage thing comes into play. The rated current is 6.7A and if I've got this right the you take the amps and divided by number of cobs ( 6.7 divided by 12 cobs = 0.55) so the cobs would be very efficient but running pretty soft. If your were to run 6 cobs @ 36v the amps per cob would be 1.116.
Well guys, did I get the math right?
I too am a newbie...someone correct me if Im wrong, but to maximize this driver one would have to run in parallel (some do not care to run cobs in parallel).
I think the voltage range you are referring to is input (it can take 120v or 240v VAC for instance)...
In series, you would have to run it @ 3.3 - 3.6A (6.7 would blow even a 3590)...
In series, @ 3.3A x 36V = 118.8 W, you could only run (2) cobs for total of 237.6W...
It seems to me, one would have to run in parallel...one could run (9) cobs @ .7A for example...
This is likely why peeps choose 240h 700 (and the like)...can run in series and dont have to mess w added safety precautions that you do in parallel...
Edit: I suppose, as you pointed out, if someone were to overcome the pitfalls of parallel wiring cobs...theoretically, one could obtain crazy levels of efficiency and drive large number of cobs w one driver (Ex: (20) 3590 cobs @ .335A )