The far red thread

BOBBY_G

Well-Known Member
yup. id buy that over your tri-pcb as far as coverage.

thats cool to double side tape to a heatsink? and run it out to 1000 mA? (for 10-15 min)
 

BOBBY_G

Well-Known Member
you know what would be awesome? a 600 mm bar with one led in the center and two more each about 30 mm from the ends

cant believe nobody thought about that combo yet
 

BOBBY_G

Well-Known Member
growmaus's vid for those who havent seen it


that tiny driver (http://shop.stevesleds.com/Meanwell-LDD-700H-Driver-654681631.htm) can do up to 24 at 700 mA (and they make a 1000 mA version as well!

the caveat being your input voltage has to be higher than your output so you end up with a handful of old cell chargers or throw down $20 or less for a decent AC>DC power supply

why cant we build a little capacitor circuit that charges all day and then fires for 10 min after power goes out?
 

hyroot

Well-Known Member
I see proof of your compulsive need to avoid all challenges to your idiot dogma.

Please explain how this statement "Only a few place in the world will plants actually get uvb outside. Pretty much where the hole in the ozone layer is." has ANY BASIS IN FACT.

We have viewed maps showing UVB radiation across the planet. We have research documenting the effects in situ of UVB on living plants. Yet by your logic "only a few place in the world actually get UVB outside." Please defend this preposterous and mistaken assertion.

Listen here you piece of shit I had to work all day. I don't have time to sit on here all day like you

If you read those nasa links air provided. It would explain why you are wrong. Uvb is only a very small percentage of it gets through the ozone layer and because of the ozone layer there's only uvb hitting the grounds surface in certain areas. The most uvb hitting the grounds surface is where the hole in the ozone layer is. No fuck off. Mic dropped.
 

testiclees

Well-Known Member
Listen here you piece of shit I had to work all day. I don't have time to sit on here all day like you

If you read those nasa links air provided. It would explain why you are wrong. Uvb is only a very small percentage of it gets through the ozone layer and because of the ozone layer there's only uvb hitting the grounds surface in certain areas. The most uvb hitting the grounds surface is where the hole in the ozone layer is. No fuck off. Mic dropped.
"Listen here"? Idiot who the heck listens to you?

UVB radiation effects the planet. Dont be a willfully ignorant cretin.
 

hyroot

Well-Known Member
"Listen here"? Idiot who the heck listens to you?

UVB radiation effects the planet. Dont be a willfully ignorant cretin.

Yeah it has an affect on the panet. But uvb doesn't make it through the ozone layer everywhere like you stated you nitwit
 

a mongo frog

Well-Known Member
Listen here you piece of shit I had to work all day. I don't have time to sit on here all day like you

If you read those nasa links air provided. It would explain why you are wrong. Uvb is only a very small percentage of it gets through the ozone layer and because of the ozone layer there's only uvb hitting the grounds surface in certain areas. The most uvb hitting the grounds surface is where the hole in the ozone layer is. No fuck off. Mic dropped.
Garden work or 9-5 type shit?
 

BOBBY_G

Well-Known Member
why cant we build a little capacitor circuit that charges all day and then fires for 10 min after power goes out?
short answer after hours of rabbit-holing:

supercapacitors come in 2.5-2.7V and with a resistor can be tuned down to the 1.8-2.25V we need

following this methodology (keeping in mind our LEDs are much brighter and more power hungry than application)

http://electronics.stackexchange.com/questions/67980/how-long-would-a-150-farad-capacitor-light-up-an-led

lets say we start with a 500 farad 2.7v capacitor ($4), little more w/protection board) and put an LED and resistor in series

at full charge: 2.7V
desired led V(per) = 2.25V
resistor V = 2.7-2.25=450 mV

LED current = 1000 mA

resistor size = 450 mv/1000 mA = 0.45 (say 0.5 ohms)

capacitor time constant (time to drop to 36.8% of voltage) = 500F x 0.5ohms = 250 sec, just over 4 min

BUT the min voltage for the diode is 1.8V, so we wold get maybe a minute out of it

lets try it starting at 500 mA

at full charge: 2.7V
desired led V(per) = 2V
resistor V = 2.7-2=700 mV

LED current = 500 mA

resistor size = 700 mv/500 mA = 1.4 ohms

capacitor time constant (time to drop to 36.8% of voltage) = 500F x 1.4 ohms = 700 sec, just over 10 min

so wed get a few minutes out of it in this case
 

BOBBY_G

Well-Known Member
option #2: charge a li-po battery like they use in toy helicopters. these are known for having high 'C' discharge rates

lets say you put XP-E leds in a room

x strings of 7 in series, a string of 7 leds would operate between 16 and 12.5V and then fall off
this is right about the voltage of a 4cell ("14.8 V") lipo battery

1 string of 7 LEDs = 1000 mA = 1 AH to run it for an hour, or 100mah to run it for 6 minutes

they make batteries in 450 and 650 mah that could run 5-7 strings of these

during day- battery charges while lights are on. lights off>relay> battery clicks from charger over to LEDs> drains in 6 minutes relay kicks back to charging when lights come on
 

BOBBY_G

Well-Known Member
moral of the story - i could have built an interval timer setup in the time it took me to research that...

BUT in the second case, the li-po battery and charger and relay is prob about the cost of the drivers you would need to run those so its like youre getting a (hack of a) solution for 'free'
 

welight

Well-Known Member
you know what would be awesome? a 600 mm bar with one led in the center and two more each about 30 mm from the ends

cant believe nobody thought about that combo yet
I know I can build it, question is does it really make sense, your paying for about 550mm of bare unused mcpcb?
Cheers
Mark
 
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