In a constant current driver, the current is held constant, but the voltage is allowed to float to whatever level it needs to be at, to maintain that constant current. In a constant voltage driver, it's the other way around. The voltage is held at a constant level, and the current is allowed to float as necessary.
Yea, I know that much.
On the hlg-240h-c1750, when you adjust the driver to 1750mA, you are in effect telling the driver to adjust the voltage to whatever level it needs to be at, so as to maintain an output current of 1750mA. If you look at the
forward voltage vs current graph that
@pop22 linked, you'll see that at 1750mA, the QB132 board will be at approximately 35v. So, if the driver is set at 1750mA and you have 3 QB132s hooked up in series, the driver output will be 105v @ 1750mA. If 4 QB132s are hooked up, then the driver will output 140v @ 1750mA.
It's confusing when you say this "On the hlg-240h-c1750, when you adjust the driver to 1750mA...", right after saying "In a constant current driver, the current is held constant, but the voltage is allowed to float to whatever level it needs to be at, to maintain that constant current."
So, basically, the qb132 doesn't "need" 36v, it varies with current, etc. etc. And that 1volt under (143v) on the 240h-c1750 doesn't matter, is what I'm hearing. Ok.
I know about fV and I've seen the graph. Whenever I try and apply the little I know and formulate a reasonably simple question...things gets confused. I thought forward voltage was defined as the minimum amount of voltage required the power/light the light. Guess not. Or not without some asterisk.
The qb132 looks like it's fV is just under 33.5v based of that graph... The flux chart goes from 32.7v to 34v.; it doesn't even show 36v on that particular page/chart, hah.
The info above says "QB132 are 36V and can be used with standard drivers...". So...is 36v the max then? "Allow tolerance of an additional 1V while matching drivers." An additional 1v allowed to the ratings in the flux characteristics chart below? Or to whatever voltage rating (cc range) a potentially paired driver can provide? (not expecting answers, just pointing out questions).
35v x1750ma x 4 boards = 245Watts, which is about the max wattage of the hlg-240h-c1750b
I also wanted to point out that if you set the driver to output 1750 mA, it wouldn't matter which driver you were using (the hlg-240h-c1750b, hlg-320h-c1750b, or the hlg-320h-c2100b) all three drivers would be outputting the same 140v @ 1750mA to the 4 QB132s.
The different drivers have different constant current regions and other shit though. Four qb132 may fall outside that range on one of these drivers (asterisk), no? But yea, I see what you're saying about the math producing the same wattage, yup.
I think you should figure out how many watts you want per sq ft. Then decide what driver you want. If you want 15W/ft², then you'd only need (15W x 30 sq ft = 450 total watts) 225W per driver, so the hlg-240h-c1750 would work. If you want 17.5W/ft², then you'd need 262W per driver, which would eliminate the 240h.
I did. It's a veg area. The area is 3x9 ish, call it 30sq/ft. 15-20w per sq/ft is generally recommended for veg for QBs, right? The boards can run a max of 75w without a heatsink. And the list of suggested drivers basically show that they're trying to power the boards between around 50w - 75w. I want the ability to run up to that 'max' of 70-75w. 30sq/ft x 17.5w (avg) is 525w (so 450-600w).
4 boards in a pack, 4x75w = 300w. 300w / 15 sq/ft = 20w per sq/ft. (this is half the area)
4 boards in a pack, 4x60w = 240w. 240w / 15 sq/ft = 16w per sq/ft. (this is half the area)
Too bad I can't devote 12 boards to it for simplicity. I might have to go with two 320w drivers then, just to have the power *available*.
Run four qb132s off a 320h-c2100b, and dim it down? Will that actually reduce current output below 2100mA, or is it just sorcery via the 3-in-1 dimming (like applying a resistance or voltage, etc.)?