There is a simple calculation to work out the cfm required to meet the desired temp rise from ambient at given wattages..
@Little Dog
This is not my work, its copied from another forum. Credit goes to Anonamiss.
It boils down to CFM = 3.16 x Watts / DT(°F)
Watts is the lighting power (and any other 'hot' things in the grow space) in Watts.
DT is the allowable temperature rise within the enclosure (i.e. desired temperature minus ambient temperature) in °F.
So, to work out the size of fan required (in CFM) simply plug your lighting Wattage into the equation along with the DT value.
An example is:
Ambient temerature = 20 °C
Target temperature of the enclosure = 25 °C
DT in °C = 25 - 20 = 5
DT in °F = 5 x (9 / 5) = 9
Lighting Wattage = 250 Watts
Plugging these values into the equation gives:
CFM = 3.16 x 250 / 9 = 87.77
This represents the actual throughput required but it doesn't take account of the static pressure necessary to overcome the system impedance (how hard the fan has to suck or blow). But for a free-air system with no ducting or filters it should be fairly accurate.
For those who want a bit more info on how to work it out, here it is.
First, you'll need to know the amount of heat that needs to be dissipated.
The general equation for heat transfer is:
q = Cp x W x DT
where:
q = amount of heat transferred
Cp = specific heat of air
DT = allowable temperature rise within the enclosure
W = mass flow
Mass flow is defined as:
W = CFM x Density
DT is the difference between the ambient air (room) temperature and the target temperature inside the grow space in °F.
At sea level the density of air is 1.2041 kg/m3 (at 20°C) and the specific heat capacity (under typical room conditions) is 1.006 kJ/kgC. After doing some substitution and conversion this gives:
CFM = 3.16 x Watts / DT(°F)