mahiluana
Well-Known Member
how to recapture the heat as energy to use for cooling the room in the summer.
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you can keep your room temp. low by using hot water in kitchen, shower, washing-machine,
swimming-pool...........the temperature of your lamp can reach ~ the temp. of your incoming service water.
how can you be shure to reach 45% light efficiency ???The setup I have is more efficient than 25/75 light/heat, it's closer to 35-45/55-65
you can find out easiely the exact values for your chip(s) and driver.
and i guess you will be surprised.
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i did a strange, "exciting" test to know this a bit more accurate.
I wired a Cree 2530/ 5000K/ T4 to a 10W @ 300mA led driver.
I wanted to be shure to use a middle class quality chip and run it under low current efficiency.
My wattmeter showed 10,9W / Vf = 32,4V @ 300mA.
All calculations of temp. change and heat energy you can do here:
https://rechneronline.de/chemie-rechner/heat-capacity.php
I wrapped the chip into a waterfilled "ballon" 0,175kg of water and switched the light on.
After 30 min. the temp. rised from 25,4°C to 40,5°C ---> 6,2W during 1800 seconds.
I estimate the power loss for the led driver ~ 0,5W
So 10,9W(powermeter) - 0,5W(led-driver) - 6,2W(heat energy) leaves 4,2W for the light.
Light efficiency is 38,5%.
Today i repeated the same test, but only 20 min. - I wanted to know more about the heat loss
or heat transfer to the ambient.
After 20 min. the temp. rised from 28,4°C to 38°C --->5,9W during1200 seconds.
Following the water temp. of the ballon cooling down in the room i measured 9 min.
to take the temp. down from 33,7°C to 32,7°C. ---> 1,2W / 9min. = 2,6W / 20min.
This must be more or less my average heat transfer loss to the ambient and is bigger than i thought. You have to add it to the bill.
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New calculation is: 10,9W total - 0,5W led driver - 8,5W heat energy --->
my light efficiency is just 26,6%.
Any coments, questions and critic is welcome - on the pics you see simple things for the measurement,
that you can find in smart lighted household.
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